Samapico Posted October 8, 2004 Report Posted October 8, 2004 wb-Lovewarjav-hm...they all pwn me, so it doesnt matterspider-..same as jav lollevi <3-gink no question about itterr-dont pay attention to terrsweasle (vermin)-anybodyshark -kent<{POST_SNAPBACK}> you didn't mention Lancaster...
Flash Fish Posted October 8, 2004 Report Posted October 8, 2004 Here's my list:Remember, I'm relatively new (first played 13.11.03, 360h usage), so it depends on what I saw in this time. It's only for pub: Warbird: Ouff... Mentorian as Baller, as Allrounder perhaps naed or LoVeWarJav: Arg, i don't like Javs too much, but i think ppl like epox aren't too bad .Spider: Tempy i guess . Shark: Mythrill Mice! (k, probably not best, but most sympathic <3), Robbel Just my 2 cents, Flash
X`terrania Posted October 9, 2004 Report Posted October 9, 2004 Yeah Cokey, it is a bit old Who is Qiu?
X`terrania Posted October 14, 2004 Report Posted October 14, 2004 Right on, look for a Qian sometime.
Cokey Flo Posted October 14, 2004 Report Posted October 14, 2004 Okay.... I'll change my signature.....
Raem Posted October 15, 2004 Report Posted October 15, 2004 Cokey has no sig, so yours owns nothing...seems about right
Raem Posted October 16, 2004 Report Posted October 16, 2004 In that case, you are applying the statement to everyone, and some people are without signatures, which means your sig owns only those with signatures, but the effect is negated when compared to the people without signatures, which results in a null value, meaning your sig owns nothing!
BeWaRe Posted October 16, 2004 Report Posted October 16, 2004 (edited) In that case, you are applying the statement to everyone, and some people are without signatures, which means your sig owns only those with signatures, but the effect is negated when compared to the people without signatures, which results in a null value, meaning your sig owns nothing!<{POST_SNAPBACK}>f(x,y,z) = x'y'+(y+xz)(x+y') = x'y'+(y+x)(y+z)(x+y') = (x'y'+y+x)(x'y'+y+z)(x'y'+y') = (x+y+x')(x+y+y')(y+z+x')(y+z+y')(x+y'+x')(x+y'+you')(you+y'+y') = (x'+y+z)(you+y'+zz') == (x'+sig+z)(x+y'+z)(x+sig+z'), meaning, I own you, all of your sigs, and all of your base. Edit: There ya go =P Edited October 17, 2004 by BeWaRe
Raem Posted October 17, 2004 Report Posted October 17, 2004 There's a syntax error in your equation...won't run(and it still does not account for the people without sigs!)
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